UNION will give all the members of SET1,SET2…. SETn. By default it will remove any duplicates.
SELECT UNION (
[Date].[Calendar Year].[CY 2010]:[Date].[Calendar Year].[CY 2014] // SET 1
,
{
[Date].[Calendar Year].[CY 2012]
} //SET 2
,
{
[Date].[Calendar Year].[CY 2013]
} //SET 3
) ON COLUMNS,
[Measures].[Sales Amount] ON ROWS
FROM [Adventure Works]
This will give use:
If we add the ALL flag duplicates will be visible:
SELECT UNION (
[Date].[Calendar Year].[CY 2010]:[Date].[Calendar Year].[CY 2014] // SET 1
,
{
[Date].[Calendar Year].[CY 2012]
} //SET 2
,
{
[Date].[Calendar Year].[CY 2013]
} //SET 3
, ALL
) ON COLUMNS,
[Measures].[Sales Amount] ON ROWS
FROM [Adventure Works]
Have Fun And Till Next Time
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